Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Test - Page 293: 9


$\theta = 30^{\circ}, 330^{\circ}$

Work Step by Step

$-3~sec~\theta +2\sqrt{3} = 0$ $\frac{-3}{cos~\theta} = -2\sqrt{3}$ $\frac{cos~\theta}{-3} = \frac{1}{-2\sqrt{3}}$ $cos~\theta = \frac{\sqrt{3}}{2}$ $\theta = 30^{\circ}, 330^{\circ}$
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