## Trigonometry (11th Edition) Clone

There is no angle $\theta$ such that $sin~\theta = 3$ Therefore, $sin^{-1}~3$ is not defined
Let $\theta = sin^{-1}~3$ Then: $sin~\theta = 3$ However: $-1 \leq sin~\theta \leq~1$, for all angles $\theta$ There is no angle $\theta$ such that $sin~\theta = 3$ Therefore, $sin^{-1}~3$ is not defined