Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Test - Page 293: 2d



Work Step by Step

RECALL: $y=\text{arcsec}{(x)} \longrightarrow \sec{y}=x$ where $y$ is in the interval $[0, \frac{\pi}{2})\cup (\frac{\pi}{2}, \pi]$. Note that: $\sec{(\frac{2\pi}{3})} = -2$ Thus, the solution to the given equation is $y=\dfrac{2\pi}{3}$.
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