Answer
$P(no~hurricane)=P(0)=0.770$
Work Step by Step
$P(x)=\frac{(λt)^x}{x!}e^{-λt}$
29 hurricanes in 111 years:
$λ=\frac{29}{111}\approx0.261$
If t = 1 (in a single year)
$P(no~hurricane)=P(0)=\frac{(0.261\times1)^0}{0!}e^{-0.261\times1}=\frac{1}{1}e^{-0.261}=0.770$
