Answer
$P(at~least~1)=0.777$
In about 777 of every 1000 5-gram samples, there will be at least 1 insect fragment.
Work Step by Step
$P(fewer~than~1)=P(x\lt1)=P(0)=\frac{(0.3\times5)^0}{0!}e^{-0.3\times5}=\frac{1}{1}e^{-1.5}=0.223$
The probability that there will be at least 1 insect fragment in a 5-gram sample is the complement of the probability that there will be fewer than 1 insect fragment in a 5-gram sample.
Using the Complement Rule (see page 275):
$P(at~least~1)=P(x\geq1)=1-P(x\lt1)=1-0.223=0.777$
