Answer
$P(x\lt2)=0.558$
In about 558 of every 1000 5-gram sample, there will be fewer than 2 insect fragments.
Work Step by Step
$P(x\lt2)=P(0)+P(1)=\frac{(0.3\times5)^0}{0!}e^{-0.3\times5}+\frac{(0.3\times5)^1}{1!}e^{-0.3\times5}=\frac{1}{1}e^{-1.5}+\frac{1.5}{1}e^{-1.5}=0.558$
