Answer
$P(more~than~one)=0.380$
In about 380 of next thousand 100 million vehicle miles, there will be more than one fatal accident.
Work Step by Step
$P(fewer~than~2)=P(x\lt2)=P(0)+P(1)=\frac{(1.32\times1)^0}{0!}e^{-1.32\times1}+\frac{(1.32\times1)^1}{1!}e^{-1.32\times1}=\frac{1}{1}e^{-1.32}+\frac{1.32}{1}e^{-1.32}=0.620$
The probability that there will be more than one fatal accident during the next 100 million vehicle miles is the complement of the probability that there will be fewer than 2 fatal accidents during the next 100 million vehicle miles.
Using the Complement Rule (see page 275):
$P(more~than~one)=P(x\geq1)=1-P(x\lt2)=1-0.620=0.380$
