Answer
$P(one~component~fail)=0.15\gt0.05$. It is not an unusual event.
$P(two~components~fail)=0.0225\lt0.05$. It is an unusual event.
Work Step by Step
$P(one~component~fail)=0.15$
Using the Multiplication Rule (see page 282):
$P(two~components~fail)=P(component~1~fail)\times P(component~2~fail)=0.15\times0.15=0.0225$
So:
$P(one~component~fail)=0.15\gt0.05$. It is not an unusual event.
$P(two~components~fail)=0.0225\lt0.05$. It is an unusual event.
