Chapter 5 - Section 5.3 - Assess Your Understanding - Applying the Concepts - Page 285: 16a

$P(all~100~bulbs~will~last~2~years)\approx0.60577$

$P(a~bulb~will~last~2~years)=0.995$ Now, using the Multiplication Rule (see page 282): $P(all~100~bulbs~will~last~2~years)=$ $P(bulb~1~will~last~2~years)\times P(bulb~2~will~last~2~years)\times ... \\...\times P(bulb~100~will~last~2~years)=$ $[P(a~bulb~will~last~2~years)]^{100}=0.995^{100}\approx0.60577$