Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 5 - Section 5.3 - Assess Your Understanding - Applying the Concepts - Page 285: 22a

Answer

$P(all~12~tests~will~be~positive)=0.99^{12}\approx0.886385$

Work Step by Step

$P(a~test~will~be~positive)=0.99$ Now, using the Multiplication Rule (see page 282): $P(all~12~tests~will~be~positive)=$ $=P(test~1~will~be~positive)\times P(test~2~will~be~positive)\times ... \\...\times P(test~12~will~be~positive) = $ $=[P(a~test~will~be~positive)]^{12}=0.99^{12}\approx0.886385$
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