Answer
$P(all~12~tests~will~be~positive)=0.99^{12}\approx0.886385$
Work Step by Step
$P(a~test~will~be~positive)=0.99$
Now, using the Multiplication Rule (see page 282):
$P(all~12~tests~will~be~positive)=$
$=P(test~1~will~be~positive)\times P(test~2~will~be~positive)\times ... \\...\times P(test~12~will~be~positive) = $
$=[P(a~test~will~be~positive)]^{12}=0.99^{12}\approx0.886385$