Answer
$P(four~auto~racing~fan~prefers~NASCAR)\approx0.12117$
Work Step by Step
$59$% $=0.59$
$P(auto~racing~fan~prefers~NASCAR)=0.59$
Using the Multiplication Rule (see page 282):
$P(four~auto~racing~fan~prefers~NASCAR)=P(auto~racing~fan~1~prefers~NASCAR)\times P(auto~racing~fan~2~prefers~NASCAR)\times P(auto~racing~fan~3~prefers~NASCAR)\times P(auto~racing~fan~4~prefers~NASCAR)=0.59\times0.59\times0.59\times0.59\approx0.12117$
