Answer
$P(Gourmet)=\frac{264}{1009}\approx0.2616$
Work Step by Step
The sample space: 1009 cases. So, $N(S)=1009$
According to the marginal distribution (see page 235) of the first column: $N(Gourmet)=264$
Using the Empirical Approach (page 258):
$P(Gourmet)=\frac{N(Gourmet)}{N(S)}=\frac{264}{1009}\approx0.2616$
