Answer
No.
Work Step by Step
Before the game starts each player has the same chance of winning. There are 5 players (sample space).
Using the Classical Method (page 259):
$P(I~win)=\frac{N(I~win)}{N(S)}=\frac{1}{5}=0.2$
But, in the present situation, $P(get~two~clubs~in~a~row)=0.03415\lt0.2$
I think it is better to give up.
