Answer
It is not surprising that none of the 5 trust organized religion.
Work Step by Step
$P(does~not~trust~organized~religion)=0.82$
The events "American 1 does not trust organized religion", "American 2 does not trust organized religion", "American 3 does not trust organized religion", "American 4 does not trust organized religion" and "American 5 does not trust organized religion" are independent.
Now, using the Multiplication Rule (see page 282):
$P(none~of~the~5~trust~organized~religion)=P(American~1~does~not~trust~organized~religion)\times P(American~2~does~not~trust~organized~religion)\times P(American~3~does~not~trust~organized~religion)\times P(American~4~does~not~trust~organized~religion)\times P(American~5~does~not~trust~organized~religion)=0.82\times0.82\times0.82\times0.82\times0.82\approx0.37074$
$P(none~of~the~5~trust~organized~religion)\gt0.05$. This event is not unusual. So, it is not surpring that none of the 5 trust organized religion.
