Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.73 - 5.92 - Learning the Mechanics - Page 256: 5.79c

Answer

$P(x\geq38)=.6950$

Work Step by Step

$q=1-p=1-.40=.60$ $\mu=np=100(.40)=40$ $\sigma=\sqrt {npq}=\sqrt {100(.40)(.60)}=4.90$ $\frac{(37+.5)-40}{4.90}=-.51$ $P(x\geq38)=1-P(x\leq37)=1-P(z\leq-.51)=P(z\geq0)+P(-.92\leq z\leq0)=P(z\geq0)+P(0\leq z\leq.51)=.5+.1950=.6950$
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