Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.73 - 5.92 - Learning the Mechanics - Page 256: 5.76c

Answer

The interval $(-.65,8.65)$ does not lie within the range from 0 to 10.

Work Step by Step

$q=1-p=1-.4=.6$ $\mu=10(.4)=4$ $\sigma=\sqrt {npq}=\sqrt {10(.4)(.6)}=1.55$ $\mu\pm3\sigma=4\pm3(1.55)=(-.65,8.65)$
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