Answer
The interval $(29.33,70.67)$ lies completely within the range from 0 to 1000.
Work Step by Step
$q=1-p=1-.05=.95$
$\mu=1000(.05)=50$
$\sigma=\sqrt {npq}=\sqrt {1000(.05)(.95)}=6.89$
$\mu\pm3\sigma=50\pm3(6.89)=(29.33,70.67)$
Statistics (12th Edition)
by McClave, James T.; Sincich, Terry T.
Published by
Pearson
ISBN 10:
0321755936
ISBN 13:
978-0-32175-593-3
Chapter 5 - Continuous Random Variables - Exercises 5.73 - 5.92 - Learning the Mechanics - Page 256: 5.76d
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
