Answer
The interval $(5.43,18.57)$ lies completely within the range from 0 to 20.
Work Step by Step
$q=1-p=1-.6=.4$
$\mu=20(.6)=12$
$\sigma=\sqrt {npq}=\sqrt {20(.6)(.4)}=2.19$
$\mu\pm3\sigma=12\pm3(2.19)=(5.43,18.57)$
Statistics (12th Edition)
by McClave, James T.; Sincich, Terry T.
Published by
Pearson
ISBN 10:
0321755936
ISBN 13:
978-0-32175-593-3
Chapter 5 - Continuous Random Variables - Exercises 5.73 - 5.92 - Learning the Mechanics - Page 256: 5.76b
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