Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.73 - 5.92 - Learning the Mechanics - Page 256: 5.79a

Answer

$P(x\leq35)=.1788$

Work Step by Step

$q=1-p=1-.40=.60$ $\mu=np=100(.40)=40$ $\sigma=\sqrt {npq}=\sqrt {100(.40)(.60)}=4.90$ $\frac{(35+.5)-40}{4.90}=-.92$ $P(x\leq35)=P(z\leq-.92)=P(z\leq0)-P(-.92\leq z\leq0)=P(z\geq0)-P(0\leq z\leq.92)=.5-.3212=.1788$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.