Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321755936
ISBN 13: 978-0-32175-593-3

Chapter 5 - Continuous Random Variables - Exercises 5.73 - 5.92 - Applying the Concepts - Basic - Page 256: 5.80a

Answer

$\mu=250$ $\sigma=11.18$

Work Step by Step

$q=1-p=1-.50=.50$ $\mu=np=500(.50)=250$ $\sigma=\sqrt {npq}=\sqrt {500(.50)(.50)}=11.18$
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