Chapter 9 - Section 9.5 - The Cross Product - 9.5 Exercises - Page 665: 7

$-4\hat{i}+7\hat{j}-3\hat{k}$

$\textbf{u}\times\textbf{v}=\begin{vmatrix}\hat{i}&\hat{j}&\hat{k}\\1&1&1\\3&0&-4\end{vmatrix}$$=\begin{vmatrix}1&1\\0&-4\end{vmatrix}\hat{i}-\begin{vmatrix}1&1\\3&-4\end{vmatrix}\hat{j}+\begin{vmatrix}1&1\\3&0\end{vmatrix}\hat{k}$ $=(-4-0)\hat{i}-(-4-3)\hat{j}+(0-3)\hat{k}$$=-4\hat{i}+7\hat{j}-3\hat{k}$