Answer
$7\hat{i}+\hat{j}+4\hat{k}$
Work Step by Step
$\textbf{u}\times\textbf{v}=\begin{vmatrix}\hat{i}&\hat{j}&\hat{k}\\0&-4&1\\1&1&-2\end{vmatrix}$$=\begin{vmatrix}-4&1\\1&-2\end{vmatrix}\hat{i}-\begin{vmatrix}0&1\\1&-2\end{vmatrix}\hat{j}+\begin{vmatrix}0&-4\\1&1\end{vmatrix}\hat{k}$
$=(8-1)\hat{i}-(0-1)\hat{j}+(0-(-4))\hat{k}$$=7\hat{i}+\hat{j}+4\hat{k}$