Answer
$-3i+2j+3k$
Work Step by Step
Let us consider $u=\lt 1,0,1 \gt$ and $v=\lt 2,3,0 \gt$
Now,
$\hat{n}=u \times v=\begin{vmatrix}i&j&k\\1&0&1\\2&3&0\end{vmatrix}$
or, $u \times v=\begin{vmatrix}0&1\\3&0\end{vmatrix}\hat{i}-\begin{vmatrix}1&1\\2&0\end{vmatrix}\hat{j}+\begin{vmatrix}1&0\\2&3\end{vmatrix}\hat{k}\\\\=(0-3)i-(0-2)j+(3-0)k$
Thus, $\hat{n}=-3i+2j+3k$
