Answer
$9\hat{i}-6\hat{j}+3\hat{k}$
Work Step by Step
$\textbf{u}\times\textbf{v}= \begin{vmatrix}i&j&k\\1&0&-3\\2&3&0\end{vmatrix}$
$=\begin{vmatrix}0&-3\\3&0\end{vmatrix}\hat{i}-\begin{vmatrix}1&-3\\2&0\end{vmatrix}\hat{j}+\begin{vmatrix}1&0\\2&3\end{vmatrix}\hat{k}$$=(0-(-9))\hat{i}-(0-(-6))\hat{j}+(3-0)\hat{k}$
$=9\hat{i}-6\hat{j}+3\hat{k}$
