Answer
(a) 0. (b) Yes.
Work Step by Step
(a) Given the three vectors, first calculate the cross product of the two vectors: $\vec v\times\vec w
=\langle (0\times1-1\times(-1)), (1\times0+1\times1), (-1\times(-1)-0\times0) \rangle
=\langle 1, 1, 1 \rangle$. Next we calculate the scalar triple product as $\vec u\cdot(\vec v\times\vec w)
=1\times1-1\times1+0\times1=0$
(b) As the scalar triple product is zero, we conclude that these vectors are coplanar.
