Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 9 - Review - Exercises - Page 673: 28

Answer

$(x-1)^2+(y+2)^2+(z-4)^2=4$

Work Step by Step

The general equation of sphere with center $C(p,q,r)$ and radius $R$ is given by: $(x-p)^2+(y-q)^2+(z-r)^2=R^2$ Here, we have center: $C(1,-2,4)$ and radius: $R=2$ $(x-1)^2+(y-(-2))^2+(z-4)^2=(2)^2$ or, $(x-1)^2+(y+2)^2+(z-4)^2=4$ Thus, the equation of sphere is: $(x-1)^2+(y+2)^2+(z-4)^2=4$
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