Answer
$x^2+y^2+z^2=36$
Work Step by Step
The general equation of sphere with center $C(p,q,r)$ and radius $R$ is given by:
$(x-p)^2+(y-q)^2+(z-r)^2=R^2$
Here, we have center: $C(0,0,0)$ and radius: $R=6$
$(x-0)^2+(y-0)^2+(z-0)^2=(6)^2$
or, $x^2+y^2+z^2=36$
Thus, the equation of sphere is: $x^2+y^2+z^2=36$
