Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 9 - Review - Exercises - Page 673: 14

Answer

$|\overrightarrow{u}|=13$; $\overrightarrow{u} \cdot \overrightarrow{u}=169$; $\overrightarrow{u} \cdot \overrightarrow{v}=2$

Work Step by Step

Here, we have $u=(5,12); v=(10-4)$ $|\overrightarrow{u}|=\sqrt {(5)^2+(12)^2}=\sqrt {169}=13$; $\overrightarrow{u} \cdot \overrightarrow{u}=(5)^2+(12)^2=169$; $\overrightarrow{u} \cdot \overrightarrow{v}=5(10)+12(-4)=50-48$ or, $\overrightarrow{u} \cdot \overrightarrow{v}=2$
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