Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 9 - Review - Exercises - Page 673: 2

Answer

$|\overrightarrow{u}|=\sqrt {29}$; $\overrightarrow{u}+\overrightarrow{v}=\lt 2,-2 \gt $; $\overrightarrow{u} -\overrightarrow{v} =\lt -8,-2 \gt $; $2 \overrightarrow{u} =\lt 10,-4 \gt $ and $3\overrightarrow{u} -2\overrightarrow{v}=\lt 21,-6 \gt$

Work Step by Step

$|\overrightarrow{u}|=\sqrt {(5)^2+(-2)^2}=\sqrt {25+4}=\sqrt {29}$; $\overrightarrow{u}+\overrightarrow{v}=\lt 5,-2 \gt + \lt -3,0\gt=\lt 5-3,-2+0 \gt =\lt 2,-2 \gt$; $\overrightarrow{u} -\overrightarrow{v}=\lt 5,-2 \gt - \lt -3,0\gt=\lt 5-(-3),-2 -0 \gt =\lt -8,-2 \gt $; $2 \overrightarrow{u}=2\lt 5,-2 \gt =\lt 10,-4 \gt $ and $3\overrightarrow{u} -2\overrightarrow{v}=3\lt 5,-2 \gt -2 \lt -3,0\gt=\lt 15,-6\gt +\lt 6,0\gt=\lt 21,-6 \gt$
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