Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 9 - Review - Exercises - Page 673: 26

Answer

$3\sqrt 2$

Work Step by Step

The distance between two points can be calculated as: $d(P,Q)=\sqrt {(y_1-x_1)^2+(y_2-x_2)^2+(y_3-x_3)^2}$ Here, we have $d(P,Q)=\sqrt {(1-0)^2+(3-2)^2+(0-4)^2}=\sqrt {1+1+16}$ or, $d(P,Q)=\sqrt {18}=3\sqrt 2$ Thus, the distance between two points is: $3\sqrt 2$
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