Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Section 7.5 - More Trigonometric Equations - 7.5 Exercises - Page 575: 65

Answer

$0.95^{\circ}$ and $89.05^{\circ}$

Work Step by Step

Step 1. We are given $v_0=2200 ft/s, R=5000ft$ Step 2. Plug-in the above numbers into the equation $5000=\frac{2200^2sin2\theta}{32}$ which gives $sin2\theta=0.03306$ Step 3. Bear in mind that $0\leq\theta\leq\frac{\pi}{2}$ which means that $0\leq2\theta\leq\pi$, we get from Step 2 that $2\theta=sin^{-1}0.03306=1.8944,178.106$ or $\theta=0.95^{\circ}$ and $89.05^{\circ}$
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