Answer
$0$, $\pi$
Work Step by Step
$\cos 2\theta-\cos^2\theta=0$
$\cos^2\theta-\sin^2\theta-\cos^2\theta=0$
$-\sin^2\theta=0$
$\sin^2\theta=0$
$\sin\theta=0$
So the only solutions for $\theta$ in $[0, 2\pi)$ are $0$ and $\pi$.
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