Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Section 7.5 - More Trigonometric Equations - 7.5 Exercises - Page 575: 28

Answer

(a) $0.15+\frac{2k\pi}{3}$ and $0.89+\frac{2k\pi}{3}$ (b) $0.15,2.24,4.34,0.89,2.98,5.08$

Work Step by Step

(a) As $csc3\theta=\frac{1}{sin3\theta}$, the equation becomes $sin^23\theta=\frac{1}{5}$ which gives $sin3\theta=\pm\frac{\sqrt 5}{5}$, $3\theta=0.46+2k\pi$ and $3\theta=2.68+2k\pi$. Thus the solutions are $\theta=0.15+\frac{2k\pi}{3}$ and $\theta=0.89+\frac{2k\pi}{3}$ where $k$ is an integer. (b) Based on the solutions from (a), within $[0,2\pi)$, $\theta=0.15,2.24,4.34,0.89,2.98,5.08$
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