Answer
(a) $\theta=tan^{-1}(\frac{10}{x})$
(b) $286.4ft$
Work Step by Step
(a) In the triangle of concern, we have $tan\theta=\frac{10}{x}$, thus we have $\theta=tan^{-1}(\frac{10}{x})$
(b) At the limit of $2^{\circ}$, we have $x=\frac{10}{tan2^{\circ}}=286.4ft$ which is the distance the sign becomes first legible.
