Answer
$\sqrt 3$
Work Step by Step
The expression fits the tangent Subtraction Formula $tan(A-B)=\frac{tanA-tanB}{1+tanAtanB}$, thus
$\frac{tan66^{\circ}-tan6^{\circ}}{1+tan66^{\circ}tan6^{\circ}}=tan(66^{\circ}-6^{\circ})=tan60^{\circ}=\sqrt 3$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 7 - Review - Exercises - Page 579: 54
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