Answer
$\frac{2x}{1-x^2}$
Work Step by Step
Step 1. Let $u=tan^{-1}x$, we have $tan(u)=x$
Step 2. Use the Double-Angle Formula, $tan(2tan^{-1}x)=tan(2u)=\frac{2tan(u)}{1-tan^2u}
=\frac{2x}{1-x^2}$
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