Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Review - Exercises - Page 579: 67

Answer

$\frac{2x}{1-x^2}$

Work Step by Step

Step 1. Let $u=tan^{-1}x$, we have $tan(u)=x$ Step 2. Use the Double-Angle Formula, $tan(2tan^{-1}x)=tan(2u)=\frac{2tan(u)}{1-tan^2u} =\frac{2x}{1-x^2}$
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