Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Review - Exercises - Page 579: 52

Answer

$\frac{1}{2}$

Work Step by Step

We recall the Double-Angle Formula $sin2\theta=2sin\theta cos\theta$ and think it in reverse, we can have $2sin\frac{\pi}{12}cos\frac{\pi}{12}=sin2(\frac{\pi}{12})=sin\frac{\pi}{6}=\frac{1}{2}$
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