Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.3 - Dividng Polynomials - 3.3 Exercises - Page 274: 56

Answer

$x-3$ and $x+3$ are both factors of P(x) since when P(x) is divided by each one, the remainder is 0. (refer to the step by step part for the solution)

Work Step by Step

RECALL: The factor theorem states that c is a zero of P if and only if x−c is a factor of P(x). $c=3$ therefore $x-c = x-3$ $c=-3$ therefore $x-c = x-(-3)=x+3$ Divide P(x) by $x-3$, and by $x-3$ using synthetic division to have:
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.