Answer
$P(\frac{1}{2})=6$, please see explanations below.
Work Step by Step
1. Use the Remainder Theorem, we can evaluate $P(c)$ as
$P(\frac{1}{2})=2\times(\frac{1}{2})^2+9\times\frac{1}{2}+1=6$
2. Use synthetic division, divide $P(x)$ by $(x-\frac{1}{2})$ as shown,
the last number of the bottom line is the remainder, which is 6.
So $P(\frac{1}{2})=6$
