Answer
$x-\frac{1}{2}$ is a factor of P(x) since when P(x) is divided by $x-\frac{1}{2}$, the remainder is 0.
(refer to the step by step part for the solution)
Work Step by Step
RECALL:
The factor theorem states that c is a zero of P if and only if x−c is a factor of P(x).
$c\frac{1}{2}2$ therefore $x-c = x-\frac{1}{2}$
Divide P(x) by $x+1$ using synthetic division to have:
