Answer
$P(x)=x^3-3x^2-x+3$
Work Step by Step
RECALL:
If $c$ is a zero of a polynomial, then $x-c$ is a factor of the polynomial.
Since -1, 1, and 3 are zeros of the polynomial, then
$(x+1), (x-1), \text{ and } (x-3)$ are factors of the polynomial.
Thus, one polynomial of degree 3 with the given zeros is:
$\\P(x) =(x+1)(x-1)(x-3)
\\P(x)=x^3-3x^2-x+3$
