Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.3 - Dividng Polynomials - 3.3 Exercises - Page 274: 54


$x-2$ is a factor of P(x) since when P(x) is divide by $x-2$, the remainder is 0. (refer to the step by step part for the solution)

Work Step by Step

RECALL: The factor theorem states that c is a zero of P if and only if x−c is a factor of P(x). $c=2$ therefore $x-c = x-2$ Divide P(x) by $x+1$ using synthetic division to have:
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