Answer
(2, 0) and (-2, 0)
See graph below
Work Step by Step
$P(x) = x^4 - 2x^3 + 8x - 16$
$P(x) = x^3 (x - 2) + 8 (x - 2)$
$P(x) = (x^3 + 8) (x-2)$
$P(x) = (x+2) (x^2 - 2x + 4) (x-2)$
Thus the zeros are (2, 0) and (-2, 0)
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 3 - Section 3.2 - Polynomial Functions and Their Graphs - 3.2 Exercises - Page 266: 42
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