Answer
(3, 0) (-3,0) (1/2,0)
See graph below.
Work Step by Step
$P(x) = 2x^3 - x^2 - 18x + 9$
$P(x) = x^2 (2x - 1) - 9 (2x - 1)$
$P(x) = (x^2 - 9) (2x-1)$
$P(x) = (x-3) (x+3) (2x-1)$
Thus the zeros are (3, 0) (-3,0) (1/2,0)
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 3 - Section 3.2 - Polynomial Functions and Their Graphs - 3.2 Exercises - Page 266: 39
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