Answer
$1$ (multiplicity of 3)$, -2, 2$
Work Step by Step
This question asks for ALL zeros of the function
Given $P(x) = x^5 - 3x^4 - x^3 + 11x^2 - 12x + 4$
See image below for synthetic division
So x = 1
$(x-1)^2 (x^3 - x^2 - 4x + 4)$
$(x-1)^2 (x-1)(x^2 - 4)$
$(x-1)^3 (x+2)(x-2)$
Factor and set P(x) = 0
Thus the solutions are $1$ (multiplicity of 3)$, -2, 2$
