Answer
Let $y=x^2$, rewrite the equation as $3y^2+5y+2=0$
or $(3y+2)(y+1)=0$ which gives $y=-2/3,-1$
Since $x^2=-2/3$ and $x^2=-1$ do not have real roots,
we proved that the original equation has no real root.
Work Step by Step
see above.
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 3 - Review - Exercises - Page 321: 56
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