Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Review - Exercises - Page 321: 59

Answer

$-3, 1, 5$

Work Step by Step

This question asks for ALL zeros of the function Given $P(x) = x^3 - 3x^2 - 13x + 15$ See image below for synthetic division So x = 1 is a zero Factor and set P(x) = 0 $x^2 - 2x - 15$ $(x-5)(x+3)$ $x = 5, -3$ Thus the solutions are $-3, 1, 5$
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