Answer
(a) $x=1$ multiplicity=3.
$x=-1/3$ multiplicity=2.
(b) see graph.
Work Step by Step
(a) Find all real zeros of P, and state their multiplicities.
Possible rational real zeros are $\pm1,\pm1/3,\pm1/9$
Test using synthetic division, we can find a zero at $x=1$ with multiplicity of 3.
The quotient is $9x^2+6x+1=(3x+1)^2$ meaning a zero at $x=-1/3$ multiplicity 2.
(b) Sketch the graph of P.
see graph.
