Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.3 - Geometric Sequences - 12.3 Exercises - Page 866: 90

Answer

$\approx 7347$ $1.08^{n}(5000)$

Work Step by Step

"x increases by $ 8\%$" = " the new value is $ 108\%$ of x" (=1.08x) Initially, (after 0 hours), $a_{1}=a=5000$ after 1 hours: $a_{2}=1.08a=1.08(5000)$ after 2 hours: $a_{3}=1.08a_{2}=1.08^{2}a=1.08^{2}(5000)$ after 3 hours: $a_{4}=1.08a_{3}=1.08^{3}a=1.08^{3}(5000)$ ... This pattern defines $a_{n}$ = number of bacteria after $\mathrm{n}-1$ hours After 5 hours, $a_{6}= 1.08^{5}(5000)\approx$7346.640384s$\approx 7347$ After n hours: $ a_{n+1}=1.08^{n}(5000)$
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