Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Review - Exercises - Page 891: 55

Answer

convergent, sum=$\displaystyle \frac{5}{7}$

Work Step by Step

An infinite geometric series is a series of the form $ a+ar+ar^{2}+ar^{3}+\cdots+ar^{n-1}+\cdots$ An infinite geometric series for which $|r| < 1$ has the sum $S=\displaystyle \frac{a}{1-r}$ If $|r| \geq 1$, the series diverges (the sum does not exist). ------------ $a=1$ $r=-\displaystyle \frac{2}{5}, \quad |r| < 1,$ so the series is convergent, $S=\displaystyle \frac{a}{1-r}=\frac{1}{1-(-\frac{2}{5})}=\frac{1}{\frac{5+2}{5}}=\frac{5}{7}$
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